Sunday, March 23, 2008

solutions to sQUIeeeZ part-4

Ans1-
28

Ans 2-
From conditions Prince has at least 3 balls and a number of balls from this sequence:
3,6,9,12,15,18,21,24.....
Also Vipul has at least 4 balls and a number of balls from this sequence:
4,8,12,16,20,24....
Moreover Keshav has at least 5 balls and a number of balls from this sequence:
5,7,9,11,13,15,17.......
So the total number of balls is at least 12 and at most 24. Also if the number of balls is even, Prince must have an odd number of balls; if the total number of balls is odd, Prince must have an even number of balls. Hence by proper logic it is revealed that, the total number of balls can not be 13 .Also total number can not be 12,14,15,16,17 because then the total number of balls each had would be known. Also the total number cannot be 18,20,21,22,23,24 because then no number of balls could be known for anybody. So total is 19.
When total is 19. Prince must have an even number of balls and from the sequences, this number must not be greater than 10. So Prince must have 6 balls. Then Vipul and Keshav together must have 13 balls, then Vipul must have either 4 or 8 balls .but not definite one.
Hence speaker is Prince.

2 comments:

Mayank Abhishek said...

What is wrong with even number of balls? Specifically 16 balls.

For 16 balls either,

Prince has 3 balls, Vipul has 4 balls and Keshav has 9 balls.

Or,


Prince has 3 balls, Vipul has 8 balls and Keshav has 5 balls.

We know the number of balls with Prince (3) but not exactly the number of balls with others.

Even according to the sequence given in your solution 16 is a possibility, 19 is definitely also correct.

Vipul said...

hey, think over your answers to part four carefully. Why 16 can't be an answer?? 16 and 19 are two candidate answers.
regards.
vipul